Code for file upload in JSP

[arbaba]

Use request object to upload file using JSP.
1.. make an html page from where u user input tag with file type..
this page should be only one input tag.... not more than one..
form tage should use encrype="multipart/form-data".
2.. then use this code... on JPS side....
this is my Bean... where i send request as parameter...
and FileServerPath is the target location.
3.. this method return false, if fails and enter the error
into ErrorMessage gloabal variable.




public boolean FileUploadProcess(javax.servlet.http.HttpServletRe quest
request,
String FileServerPath)
{
String contentType = request.getContentType();
if ((contentType != null) &&
(contentType.indexOf("multipart/form-data") >= 0))
{
try
{
DataInputStream in = new
DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength)
{
byteRead = in.read(dataBytes, totalBytesRead,
formDataLength);
totalBytesRead += byteRead;
}
String file = new String(dataBytes);
String saveFile =
file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,
saveFile.indexOf("\""));
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,
contentType.length());
//out.println(boundary);
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;

int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0,
boundaryLocation)).getBytes()).
length;

String tmp_file = saveFile.toLowerCase();
if (tmp_file.equals(this._GIF) ||
tmp_file.equals(this._JPEG) ||
tmp_file.equals(this._JPG) || tmp_file.equals(this._PNG))
{
this.FileUserName = saveFile;
this.FileNewName = (new java.util.Date().getTime()) +
saveFile;
//System.out.println("File path = " +
FileServerPath+this.FileNewName);
FileOutputStream fileOut = new
FileOutputStream(FileServerPath +
this.FileNewName);

fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
return true;
}
else
{
this.ErrorMessage = "Invalid File Format. " +
"File Format should be .png, .gif,
.jpg or .jpeg.";
return false;
}
}
catch (Exception exception)
{
this.ErrorMessage = exception.getMessage();
return false;
}
}
else
{
this.ErrorMessage = "Ilegal ENCTYPE : must be
multipart/form-data\n" +
"ENCTYPE set = " + contentType;
return false;

}
}

[sportlover]

thanks for sharing this i am looking for the same.

[computerlaptop]

Hi
I am trying to upload file from cleint machine to the database in the server side using Java.I have to give it a name and ID before saving it to the database. I am also using Tomcat.I am a novice in this field.
Any suggestion,direction or sample would be a great help and would be greatly appreciated.
Thanks

[vanhelsing]

thanks for sharing.

[jamesprivateryan]

thanks for sharing